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50分！VB程序高手進！用VB程序?qū)崿F(xiàn)曲柄連桿機構(gòu)運動

這個程序怎么做？（參考圖片我空間相冊里面有）誰能幫我組出來，源代碼以及控件，控件應該怎么建立？盡量要源代碼，控件的建立用語言描述吧！多謝了！好的答案給50分哈！！: 問提問者：網(wǎng)友 | 2018-08-21

最佳回答

'新建窗體，添加command1,label1,hscroll1,timer1,picture1 Const pi = 3.1415926 Dim angle As Integer Private Sub Form_Load() '調(diào)整空間尺寸，位置及初始參數(shù) Me.ScaleMode = 3 Me.Caption = "曲柄滑塊機構(gòu)的演示" Me.Width = 5000 Me.Height = 3500 Picture1.ScaleMode = 3 Picture1.AutoRedraw = True Picture1.Move 0, 0, Me.ScaleWidth, 150 Command1.Caption = "開始(&B)" Command1.Move 20, 160, 70, 30 Label1.Caption = "速度：" Label1.Move 120, 170, 100, 30 HScroll1.Min = 1 HScroll1.Max = 20 HScroll1.Move 160, 160, 140, 30 Timer1.Interval = 20 Timer1.Enabled = False End Sub Private Sub Command1_Click() Timer1.Enabled = Not Timer1.Enabled If Timer1.Enabled Then Command1.Caption = "暫停(&S)" Else Command1.Caption = "開始(&B)" End If End Sub Sub draw(ByVal ox As Integer, ByVal oy As Integer, ByVal orad As Integer) 'ox,oy圓心坐標,orad半徑 angle = (angle + HScroll1.Value) Mod 360 xo = ox + orad * Cos(angle * pi / 180) '圓周上的鉸鏈點坐標(xo,yo) yo = oy + orad * Sin(angle * pi / 180) xs = Sqr((4 * orad) ^ 2 - 10 ^ 2) + xo '滑塊的左邊界x坐標，連桿長度取4*orad,滑塊高度取20(像素) Picture1.BackColor = Picture1.Ba: 回答者：網(wǎng)友

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